F(x)=-x^2+4x-5

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Solution for F(x)=-x^2+4x-5 equation: 



(F)=-F^2+4F-5

We move all terms to the left:

(F)-(-F^2+4F-5)=0

We get rid of parentheses

F^2-4F+F+5=0

We add all the numbers together, and all the variables

F^2-3F+5=0

a = 1; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·1·5
Δ = -11
Delta is less than zero, so there is no solution for the equation

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